为线程执行设置timeout

package com.test.threads;

import java.util.concurrent.ExecutionException;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
import java.util.concurrent.Future;
import java.util.concurrent.TimeUnit;
import java.util.concurrent.TimeoutException;

/**
 * @author Hawkins
 *
 *
 *在指定时间内执行某个task，超时则退出执行。
 */
public class TimedCall {
	public static void main(String[] args) throws InterruptedException,
			ExecutionException, TimeoutException {
		long timeout = 1000;// 任务必须在设定时间内完成，否则任务将被强制关闭
		long timeNeed = 2000;// 任务完成需要的时长。
		TimeUnit timeUnit = TimeUnit.MILLISECONDS;// 时间单位
		ExecutorService executor = Executors.newSingleThreadExecutor();// 高级并发API

		Runnable task = new MyThread(timeNeed, timeUnit);

		while (!timedCall(executor, task, timeout, timeUnit))
			;// 在某些场景下，需要不断尝试执行任务，直到能够在限定时间内执行完毕。

	}

	private static boolean timedCall(ExecutorService executor, Runnable c,
			long timeout, TimeUnit timeUnit) throws InterruptedException,
			ExecutionException {
		// FutureTask<?> task = new FutureTask<Object>(c, null);
		// executor.execute(task);
		//		
		// task.get(timeout, timeUnit);
		Future<?> future = executor.submit(c);
		try {
			future.get(timeout, timeUnit);
			return true;
		} catch (TimeoutException e) {
			future.cancel(true);// 参数设为true，向执行线程发送中断通知。否则，允许已经启动的线程继续执行直到完成任务。
			System.err.println("任务执行超时,强制退出");
			return false;
		}
	}
}

class MyThread implements Runnable {
	long timeLong = 0;// how long thread running will cost
	TimeUnit timeUnit;

	public MyThread() {
	}

	public MyThread(long milli, TimeUnit timeUnit) {
		this.timeLong = milli;
		this.timeUnit = timeUnit;
	}

	@Override
	public void run() {
		System.out.println("---------" + Thread.currentThread().getName()
				+ "开始执行,时长[" + timeLong + "]------");
		try {
			Thread.sleep(timeLong);
		} catch (InterruptedException e) {
			System.err.println("线程中断,退出");
			return;// 必须响应中断，否则无法退出线程。在退出之前你可能还需做一些资源回收等等。
		}
		System.out.println("---------" + Thread.currentThread().getName()
				+ "执行完毕,时长[" + timeLong + "]------");

	}
}

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