Quickest way to convert XML to JSON in Java - Stack Overflow
The JSON in Java page on json.org has some great resources.
Looks like XML.java and JSONML.java are the classes you're looking for:
public class Main { public static int PRETTY_PRINT_INDENT_FACTOR = 4; public static String TEST_XML_STRING = "<?xml version=\"1.0\" ?><test attrib=\"moretest\">Turn this to JSON</test>"; public static void main(String[] args) { try { JSONObject xmlJSONObj = XML.toJSONObject(TEST_XML_STRING); String jsonPrettyPrintString = xmlJSONObj.toString(PRETTY_PRINT_INDENT_FACTOR); System.out.println(jsonPrettyPrintString); } catch (JSONException je) { System.out.println(je.toString()); } } }
Looks like it does the job. Output is:
{"test": { "attrib": "moretest", "content": "Turn this to JSON" }}
Expanded from my original entry. I hope this helps.