Android 中通过 URI 实现 Web 页面调用本地 App

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//调用地图应用显示地理位置     
Uri uri = Uri.parse("geo:38.899533,-77.036476");     
Intent it = new Intent(Intent.Action_VIEW, uri);     
startActivity(it);     
//调用拨号程序     
Uri uri = Uri.parse("tel:18616612345");     
Intent it = new Intent(Intent.ACTION_DIAL, uri);        
startActivity(it);     

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<a href="MY_SCHEME:\\MY_HOST:MY_PORT\MY_PATH\?arg0=0&arg1=1">Open App</a>     

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webView.setWebViewClient(new WebViewClient(){     
	@Override     
	public boolean shouldOverrideUrlLoading(WebView view, String url) {     
		Uri uri=Uri.parse(url);     
        	if(uri.getScheme().equals(MY_SCHEME)     
        		&& uri.getHost().equals(MY_HOST)     
        		&& uri.getPort() == MY_PORT     
        		&& uri.getPath().equals(MY_PATH)){     
        		String arg0 = uri.getQueryParameter("arg0");     
        		String arg1 = uri.getQueryParameter("arg1");     
        		//TODO     
        	} else {     
        		view.loadUrl(url);     
        	}     
		return true;     
	}     
});     

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<activity     
	android:name=".activity.UriActivity"     
	android:exported="true">     
	<intent-filter>     
		<action android:name="android.intent.action.VIEW"/>     
		<category android:name="android.intent.category.DEFAULT"/>     
		<category android:name="android.intent.category.BROWSABLE"/>     
		<data android:scheme="MY_SCHEME"     
			android:host="MY_HOST"     
			android:port="MY_PORT"     
			android:path="MY_PATH"/>     
	</intent-filter>     
</activity>