应用jQuery技术读取经过MappingJacksonJsonView转化的集合对象
- - ITeye论坛最新讨论经过Spring MVC MappingJacksonJsonView转化后返回的JSON数据:. Spring MVC控制器处理来自“test/getJSON”的请求:. strResult += "
经过Spring MVC MappingJacksonJsonView转化后返回的JSON数据:
{
"users": [
{
"userid": null,
"username": "user_01",
"pass": "123"
},
{
"userid": null,
"username": "user_02",
"pass": "456"
}
]
}
Spring MVC控制器处理来自“test/getJSON”的请求:
@RequestMapping("/getJSON")
public ModelAndView getJSON() {
System.out.println("getJSON");
ModelAndView mav = new ModelAndView();
List<User> users = this.getUsers();
mav.addObject("users", users);
mav.setViewName("testJSON");
return mav;
}
在页面读取返回数据:
<script type="text/javascript">
$(function(){
$("#testJson").click(function(){
$.ajax({
type:"GET",
url:"http://localhost:8080/SpringTest/test/getJSON?content=json",
dataType:"json",
contentType:'application/json;charset=UTF-8',
success:function(data){
$("#result").empty();
var strResult = "";
var users = data.users;
for(index in users){
strResult += "<div class='comment'>用户名:" + users[index].username + "<br />密码:" + users[index].pass + "<hr /></div>";
}
$("#result").html(strResult);
},
error:function(){
alert("error.");
}
});
});
})
</script>
在配置$.ajax()的url时,我写的url明显是冗长的。但是目前我还没有找到一个正确的、合理的处理方式。
密码:" + users[index].pass + "